(5/x+4)-(4/x-4)=(2x/x^2-16)

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Solution for (5/x+4)-(4/x-4)=(2x/x^2-16) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x-(4/x)+4+4 = (2*x)/(x^2)-16 // - (2*x)/(x^2)-16

5/x-(4/x)-((2*x)/(x^2))+4+4+16 = 0

5/x-4*x^-1-2*x^-1+4+4+16 = 0

-1*x^-1 = -24 // : -1

x^-1 = 24

-1 < 0

1/(x^1) = 24 // * x^1

1 = 24*x^1 // : 24

1/24 = x^1

x = 1/24

x = 1/24

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